16=x+4+(2^4-6)

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Solution for 16=x+4+(2^4-6) equation: 



16=x+4+(2^4-6)

We move all terms to the left:

16-(x+4+(2^4-6))=0



We calculate terms in parentheses: -(x+4+(2^4-6)), so:

x+4+(2^4-6)

We add all the numbers together, and all the variables

x+14

Back to the equation:

-(x+14)



We get rid of parentheses

-x-14+16=0

We add all the numbers together, and all the variables

-1x+2=0

We move all terms containing x to the left, all other terms to the right

-x=-2

x=-2/-1

x=+2

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